Anomalous Coffee Machine Apr 2026

def press_button_B(self): if self.coffee_in_pot > 0: self.coffee_in_pot += 1 return f"Coffee added. Total: {self.coffee_in_pot} cup(s)" else: return "Button B requires coffee to already be in the pot."

class CoffeeMachine: def __init__(self): self.coffee_in_pot = 0 Anomalous Coffee Machine

def solve(): machine = CoffeeMachine() sequence = ["A", "A", "B"] for action in sequence: if action == "A": print(machine.press_button_A()) elif action == "B": print(machine.press_button_B()) def press_button_B(self): if self

solve() This code implements the coffee machine's behavior and then uses a predefined sequence ("A", "A", "B") to demonstrate getting exactly 3 cups of coffee. The Anomalous Coffee Machine problem is a fun logic puzzle that requires understanding the conditions under which each button works. The solution is straightforward once you grasp the button's behaviors. The solution is straightforward once you grasp the

def press_button_A(self): if self.coffee_in_pot == 0: self.coffee_in_pot += 1 return f"Coffee added. Total: {self.coffee_in_pot} cup(s)" else: return "Button A won't add coffee if there's already coffee."